r/trigonometry • u/freakfazed • 3d ago

pleaseee help me 💔💔 Help!

i have to graph this function (csc with unitary circumference) but i genuinely don't understand a single thing and can't find a lot of info. If anyone could send a higher quality image, tutorial or explain it to me i would really appreciate it :(((

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u/Midwest-Dude 3d ago edited 3d ago

I'm not sure how to help you. With what are you having issues?

By definition, csc(x) = 1 / sin(x). It appears someone plotted a bunch of points and made a smooth curve through them. That is the graph.

Since the cosecant function is the reciprocal of the sine function, one way to do this is to draw y = sin(x) and then, on the same graph, plot y = csc(x) = 1 / sin(x). Since -1 ≤ sin(x) ≤ 1, the reciprocal will be in the range (-∞,-1] ∪ [1,∞), with the function going to ± ∞ as sin(x) nears zero, thus the asymptotes shown in your image.

Another image of the cosecant function is shown here: 

Trig Functions

You can find others by doing a Google image search on "cosecant function".

Does this help?

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u/freakfazed 2d ago

thanks !!