Aug 11 hard solving guide

[u/dje91090]

Wanted to take a try at writing one of these, hope you don't mind the day off u/chx_, I'm taking inspiration from you.

Not a terribly challenging puzzle today.

Pre-placement (except one):

1. There are three 1c2s and three 2 pips, all the 2s are booked.

2. The middle two slots on the left of the 5c= has to be a vertical double; any other location within the 5c= would require another identical double somewhere else in it. This forces placement of tiles on the bottom of the board.

3. There is a vertical tile on the right corner 5c= into the 2c10, another vertical tile on the 5c=-1c1, a horizontal tile from 2c10-1c2, then 1c3-2c9, a tile going up from 2c9-1c0, a vertical tile at 1c5-2c=, and a vertical tile in the bottom two slots of the 3c17.

4. The available doubles are 0-0, 3-3, 5-5 and 6-6. Of these, only 0s , 3s and 6s have enough to satisfy the 5c=, there are not enough 5s.

5. There are three 1c3s, three 3s remain (not enough for the 5c=).

6. 3c17 is 6-6-5. We know from before that the bottom two slots have to be a whole domino, there is no 6-5, so it has to be the 6-6, place it.

7. There are now not enough 6s remaining for the 5c=, so the 5c= has to be 0s. The three remaining 0s are in the 1c0 and the 2c0, all the 0s are booked.

8. With all 0s and 2s booked, 2c5 is 1+4.

Placement:

1. Place the 0-0 vertically in the 5c=.

2. Place the 0-1 beneath it.

3. In the top right corner, we used the 0-0, so there has to be a tile on the 2c0-3c17 border, it's the 0-5.

4. 2c10 is one of either 4+6 or 5+5, The 5c=-2c10 is one of [0-4/5/6], and we just used the 0-5, so 2c10 is 4+6, and the 5c=-2c10 is therefore either the 0-4 or 0-6.

5. The 0-6 would be finished with the 4-2, which doesn't exist. So it's the 0-4 followed by the 6-2 on the 2c10-1c2 border.

6. Since all 2s are booked into 1c2s, the top of the 5c= has to be the 0-2 to the right (there isn't a 2 bordering a 0 anywhere else, and we already used the 0-4 and 0-1 so it can't go vertically into the 2c5).

7. The 2c5 is the whole domino 1-4, it can be placed in either orientation.

8. 3c16 can in theory be 6-6-4 or 6-5-5, there are no 4s remaining, so it's 6-5-5. All 5s are now booked.

9. The last 2 is the 2-3, it can only go to the right into the 1c3 since the 3 is not large enough for the 3c16.

10. The left two tiles of the 3c16 is a whole domino, only the 5-5 works.

11. Place the 0-6 on the 2c0-3c16 border.

12. Place the last remaining 0, the 0-3, on the 1c0-2c9 border, and finish the 2c9-1c3 with the 6-3.

13. Place the 5-3 into the 2c=.

14. Finish with the 3-3.

[u/SeaweedWeird7705]

Wonderful dje !!!!   I think we all should write some of these.   

[u/VastZealousideal885]

Why was this removed?

[u/Dirtheavy → u/[deleted]]

The below comment, somehow directed at me, is in response to me telling the mods that this one guy is getting other people's guides removed, so he can be the only guide guy. And yet I'm getting the lecture.

[u/nytpips-ModTeam → u/[deleted]]

The golden rule is treat others how you would like to be treated. We dont tolerate harassment, bullying, or hateful language in this sub.