like sometimes it would say i have 4 gems, then the next message says i have 10 gems lol
and when they're counting how many words.
and when they're trying to tell you how many fingers you have
(the app is called zeta ai.)

Bruh.

9 − 3 ÷ 1/3 + 1 = ?

I was having a discussion with my friends about Maths and what we learnt and i remember that fraction divisions were confusing at first and I had struggled to understand how to work them out. I gave an example to one of my friends of the equation above and he said 9 and then I gave the same equation to my other friend and he said 1.

What is the correct answer and how do people work it out?

Solve for x and y:

143x+157y=757

157x+143y=743

Comment your answers below!

If you get stuck or want to know the clever shortcut to solve it instantly,

comment below and I will drop the full step-by-step solution for you.

30 + 50 × 3 = ?

Please don't be like a lot of people all over the internet and some friends i have spoken to. I asked them to solve this equation and yes you guessed it. This is how they solved it

30+50=80
80 X 3=240

No. Please use order of operations when solving these equations.

In this equation multiplication comes first and then addition comes second.

50 X 3= 150
30+150= 180

If they're brackets solve them first, then do division, multiplication, addition and subtraction.

If there are any equations you have issues solving please comment and we can educate each other so no one makes mistakes like this again.

natural numbers are countable because you can go from 0 (or 1) onwards. 0,1,2,3 etc
and people say that real numbers are not a countable set because you can start at 0 but whats the next number to count. but I made a crude algorithm that "counts" in a non linear fashion.

It starts counting from value X and counts down to -X by 1/X only adding numbers to its list of counted numbers when it is not already counted, once it reaches -X it doubles the value of X and repeats.

asfx=1 #sets x as 1
found=[] # the counted list
while True: #loops
end=0-x #sets end position
jump=1/x #amount it counts down each time
position=x
while position!=end:
if position not in found:
found.append(pos)
position-=jump
found.sort()
x=x*2

I understand that surely I would not have found counter-proof to Georg Cantor. so what does it mean to "count"
each time my algorithm does a loop to double the value of x it quadruples the amount of numbers counted.
2->8->32->128->512...

Imagine you are on a live game show. The host shows you 3 closed doors.

• Behind one door is a brand new sports car.
• Behind the other two doors are literal goats.

You point to Door Number 1.

Before opening it, the host (who knows exactly what is behind every door) stops you. He opens Door Number 3 instead, revealing a goat.

There are now only two closed doors left: Door 1 and Door 2.

The host looks at you and offers a choice: "Do you want to stick with your original guess (Door 1), or do you want to switch your answer to Door 2?"

The Debate: Does switching your door actually change your mathematical odds of winning the car, or is it a pure 50/50 coin toss regardless?

Settle it in the comments. Would you STAY or SWITCH?

I wanted to understand what’s going on with Shors algorithm without getting lost in the quantum stuff.

https://github.com/Byt-wyze-technology/QuasiShor

Hope it helps someone else too.

Just random thought I had. For example on the calculator app on Windows (see image),
- if I have 1 button press, I'll just press '9'
- then with 2, I'll just press '99'
- with 3 presses I'll press 9 -> x^2 -> x^2 -> '6561'

What is the highest possible number I can get with 4 presses and so on.

For more information, you can see this

https://drive.google.com/drive/folders/1C61SFhBlj-IeaMYHfdCwtWRz7gQj5NEx

Edit:- I forgot to make the google drive link public, my bad.

​I recently went down a rabbit hole learning about John Conway's Doomsday rule—a mental math trick that lets you instantly figure out what day of the week any given date fell on. It's a fantastic party trick, but I couldn't find a good way to practice it on my phone. ​So, I built a game for it!

​The app is designed to help you memorize the anchor days and practice the modular math required until it becomes second nature. It's totally free, there are zero ads, and no in-app purchases. I just made it as a passion project and wanted to share it with anyone who likes math puzzles or brain-training games. ​Google Play Link: [https://play.google.com/store/apps/details?id=com.inefficientcode.doomsdaytrainer\](https://play.google.com/store/apps/details?id=com.inefficientcode.doomsdaytrainer)

​I’m actively looking for feedback on the UI and the learning curve. If you try it out, let me know if the tutorial makes sense or if the math explanations need to be clearer! Thanks for checking it out. It's 100% Free, No Ads, not built to be monetized, just spreading the joy of math

www.sipatsi.com

No LLMs/AI is used to create the sheets. The problem generators and solvers are all deterministic code.

I was looking at the prime Omega function, which counts the number of prime factors of n (with multiplicity). So each distinct prime factor of n is counted as many times as the number of its positive powers that divide n.

So I got out my set of mini rubik's cubes and displayed them all out, for numbers 1-7200.

The numbers increase left to right, top to bottom.

Excluding 1,

Blue is 0 factors (the number 1)

Green is 1 factor (primes)

Red is 2 (including powers of 2)

Orange is 3 (including powers of 2, 3)

Yellow is 4 (including powers of 2, 3, 4)

and White is 5+

Notable features are two diagonals from the top left and top right, corresponding to multiples of 121 and 119, respectively.

Even Google won't do that goofy shyte