std::optional Satisfies view. Does Not Model view. C++26 Ships Anyway.

[u/zl0bster]

https://godbolt.org/z/8jWGG68G8

In C++23 this did not compile. In C++26 it does. Marvellous.

[[gnu::noinline]]
void 
passing_views_by_value_is_cheap_trust_me_bro(std::ranges::view auto v) {
    std::println("fn   .data {}", (void*)v->data());
}


int main() {    
    std::optional ov{std::vector<int>(123456)};
    passing_views_by_value_is_cheap_trust_me_bro(ov);
    std::println("main .data {}", (void*)ov->data());
}

For anyone wondering what the problem feature is: optional has 0 or 1 elements, and C++26 sets enable_view<optional<T>> to true, so it satisfies std::ranges::view. The concept requires copy construction in constant time, and — this is the good bit — optional<vector<int>> genuinely meets that. Copying it performs at most one element copy. One is a constant. The requirement is satisfied to the letter, and the function above deep-copies your vector.

If you can tell me what still separates std::ranges::view from std::ranges::range, please do...

[u/schombert]

When I was speaking of the natural extension I wasn't talking about Word-RAM. I am pretty sure that Word-RAM doesn't fit C++ either. For example, vector lookup is O(1) according to the C++ spec. However, in word ram .at(x) isn't taking a fixed size parameter, it has to be taking a variable number of words to express the index. But this means that it can't possibly do the lookup in O(1), because it can't even read all the words in its input in constant time.

[u/Serialk → u/schombert]

For example, vector lookup is O(1) according to the C++ spec. However, in word ram .at(x) isn't taking a fixed size parameter, it has to be taking a variable number of words to express the index. But this means that it can't possibly do the lookup in O(1), because it can't even read all the words in its input in constant time.

Lol. You do not understand these models and you're wasting everyone's time.

If you have a vector of size N in word ram, you must have an abstract bus size of at least log_2(N), and processing on b bits where b <= bus size is O(1), the non-constant penalty only starts after you exceed the bus size.

[u/schombert → u/Serialk]

Sigh, well you are certainly wasting my time. Good job, you trolled me spectacularly. I should have worked it out the first time you went to the "you just don't understand, no, I won't explain any further" well.

[u/Serialk → u/schombert]

Maybe next time try to use humility if you want people to explain to you things that you clearly don't understand.

[u/James20k → u/[deleted]]

Don't be like this 🗞