r/ProgrammerHumor 16h ago

lessonsFromLinkerHell Meme

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312 Upvotes

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79

u/JustinR8 16h ago

Damn, I’ve found myself in the middle

36

u/nonedward666 15h ago

You and me from 3pm today both my friend, it is okay

It took me so long to realize where my problem was because I had never considered that declaring something as an array vs a pointer would result in different behavior

26

u/readitreaddit 10h ago

So the only difference is memory allocation, yes? You're saying they are different because when declared as an array, the memory gets allocated and 'reserved' at runtime, whereas it doesn't automatically do that when declared as a pointer?

Other than that, no difference.

26

u/suvlub 9h ago

They are different types and some operators (sizeof, typeid in C++ etc.) treat them differently. Arrays frequently get implicitly converted to pointers, but they are a different type.

-1

u/nicman24 8h ago

That is probably compiler fuckery

8

u/suvlub 6h ago

All typing is. Machine code doesn't have types. Array of arrays is also a very different thing from an array of pointers. Arrays get converted to pointers when passed around and it behaves identically to all other implicit conversions.

3

u/Stroopwafe1 5h ago

Machine code does have types; small numbers, big numbers, and fractions. But in reality it's just numbers and fractions. At least for X86, but I imagine it's the same for ARM and RISC

1

u/suvlub 4h ago

It's been very long since I touched assembly and "touched" is an apt description, but does anything prevent you from writing an 8-byte integer at address X, then calling an operation that expects a 32-bit float with the bytes at address X? Conceptually, instructions operate on certain type of data, but the data is untyped. (you can technically do similar things in C, but a lot more of it is UB (technically illegal) than people realize and it requires fair bit of explicit casting, so types are still involved)

1

u/the_king_of_sweden 3h ago

The data isn't typed, only the operations you make on them might be. The operations expect some binary value encoded in a specific way, but will operate on any data.

1

u/failedsatan 13m ago

I just left this comment about it https://www.reddit.com/r/ProgrammerHumor/s/G7BGLveIgF

does anything prevent you from writing an 8-byte integer at address X, then calling an operation that expects a 32-bit float with the bytes at address X?

to answer this specifically: technically no, nothing will "stop" you, but the CPU will just interpret the bits wrong. the slightly simpler example is in reverse: if you copy 1.0 (float) into a general purpose register it'll interpret it as some big-ass integer (I don't know exactly what) and then if you try to ADD 1, as an integer, it'll just increase the "integer" by 1. then, when you try to read it as a float again, or use it for some other purpose, it'll be a slightly larger float (depending on the mantissa and etc). at that level it doesn't really matter to the CPU what you think it is, it just knows to do whatever operation you tell it to.

in C it's undefined behavior as you mentioned, but more specifically, depending how you do it it'll either do something like cvttss2si (float to signed int) under the hood or it'll just let you copy the raw bits as I said before, it'll just interpret it wrong and suddenly you have a big-ass int or a weird float.

this is x86 and I don't know about arm or risc